做实验时碰的到一道shell编程题:
输入一个人的出生日期，计算此人今年多少岁，并计算今天距此人今年生日还有多少天
本来想偷懒百度抄一下的结果翻了几页都没有, 算了还是自己写吧
脚本很简单, 主要是用date命令
#!/bin/bash #create By Merack #[email protected] #get the current year, month, day currentYear=`date +"%Y"` currentMonth=`date +"%m"` currentDay=`date +"%d"` #check whether the birthday has passed in this year if [[ currentMonth -lt $2 ]] then let "passFlag=0" elif [[ currentMonth -eq $2 ]] then if [[ currentDay -gt $3 ]] then let "passFlag=1" else let "passFlag=0" fi else let "passFlag=1" fi #get age if [[ $passFlag -eq 0 ]] then let "age=$currentYear-$1-1" else let "age=$currentYear-$1" fi echo "your age: $age" #get next Birthday if [[ passFlag -eq 1 ]] then echo "Your birthday has passed in this year" let "nextYea=currentYear+1" nextBirthday=$nextYea-$2-$3 nowStr=`date +"%s"` nextBirStr=`date -d "$nextBirthday" +"%s"` let "interval=(nextBirStr-nowStr)/60/60/24" echo "Your next birthday is: $nextBirthday and $interval days left" else nextBirthday=$currentYear-$2-$3 nowStr=`date +"%s"` nextBirStr=`date -d "$nextBirthday" +"%s"` let "interval=(nextBirStr-nowStr)/60/60/24" echo "Your next birthday is: $nextBirthday and $interval days left" fi
运行结果:
